0000005871 00000 n produced by thin film interference in the wedge of air between the two glass slabs. 0000002721 00000 n In addition to the path length difference, there can be a phase change. 0000002200 00000 n The light reflected from any one 34 0 obj<>stream 1. 0000001272 00000 n Thin film of oil. Interference of direct and reflected light from a point source. 0000072368 00000 n Thin Film Interference 12 n1 n2 n3 n1 endobj 0000003368 00000 n Thin film of water. �W6��o7M�����0g�;_�r{�D�0@`ެ����m�n�i�� ]���b�3J�Q!��N�nQz����G������. �Kzs�$ f����B9j�S1����o�>|�G`rfyS(�S\ p7��Hd\b ��Lـ }x����F�&� �)-��6ɛ_���Ǜ�����$��Q����D�9���Xc���:����|������/7������z������>ް����KR�>Q�Ln�ZЭ���Ն�ޭ��?Pڬ��vM�d'rZ�����%o>Im� trailer When light hits a material that has multiple layers, each layer can reflect light. 0000007629 00000 n 32 33 0000006507 00000 n 0000004800 00000 n <<71f7b7fd265e8a4f803a19a221e7a725>]>> O���꼢��FW�o��� ������VĿ०wK��7D���95BS��͒���8����F�5����>�3Υ 0000058704 00000 n This film is really much thinner than either slab. 0000072630 00000 n endstream endobj 33 0 obj<> endobj 35 0 obj<> endobj 36 0 obj<>/ProcSet[/PDF/Text]/ExtGState<>>> endobj 37 0 obj<> endobj 38 0 obj<> endobj 39 0 obj<> endobj 40 0 obj<> endobj 41 0 obj<> endobj 42 0 obj<> endobj 43 0 obj<>stream Antireflection coating with a TiO 2 thin film. << /Length 1 0 R /Filter /FlateDecode >> In addition to the path length difference, there can be a phase change. 0000058475 00000 n Given, µ = 4/3, λ1 = 6.1 x 10-7 m λ2 = 6.0 x 10-7m solution: Sin i = 4/5 µ = Sin i / Sin r Sin r = sin i / µ = ⅘ / 4/3 = sin r = ⅗ = 0.6 cos r = √1 – sin2r = 0.8 Given two consecutive fringes are overlapping, nλ1 = (n + 1)… 0000072823 00000 n 欓V+�n``h��ހ��AD�Y��i�V���:��,��8#N&��g1�ͤ�S�(����yZl��\A�� �(� ��9LJJ@���jDG�m@ ������X ,�� �0�!���s�L������~0$0�e�e�����I���i9�"�������3<31cx�0��7�N.oN��s�A� bk� �8� 0 stream

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